1. Diket SPLDV 5x-4y=-1 10x-2y=3 Selesaikan dgn metode eleminasi 2. Diket SPLDV 2x-3y=-10 x+2y=2 Selesaikan dgn metode substitusi

1) eliminasi:
nilai y=5/6
5x–4y=–1 x2
10x–2y=3 x1
.........................
10x–8y=–2
10x–2y=3
.........................–
–6y=–5
y=5/6

nilai x=7/15
5x–4y=–1 x1
10x–2y=3 x2
................................
5x–4y=–1
20x–4y=6
..........................–
–15x=–7
x=7/15
2)substitusi:
nilai y=2
2x–3y=–10 .........(1)
x+2y=2 ................(2) –> x=2–2y .......(3)
substitusikan pers(3) ke pers(1)
2(2–2y)–3y=–10
4–4y–3y=–10
–7y=–14
y=2

nilaix=–2
substitusikan y=2 ke pers(2)
x+2(2)=2
x+4=2
x=–2
semoga membantu ya....