Koordinat titik balik mksimum grafik fungsi f (×)=x^3-3×^2-9×+9 adalah

f(x) = x³ - 3x² - 9x + 9

titik balik ---> f'(x) = 0

f'(x) = 0
3x² - 6x - 9 = 0
x² - 2x - 3 = 0
(x - 3)(x + 1) = 0
x = 3 atau x = -1

f(-1) = (-1)³ - 3(-1)² - 9(-1) + 9 = 14 (maks)
f(3) = 3³ - 3 . 3² - 9.3 + 9 = -18 (min)

titik balik maksimum = (-1 , 14)