Mohon bantuannya temen2, tmakasih :)

ingat log a/log b = ᵇlog a
log a + log b = log a.b
log a - log b = log a/b

²log x (2x-3)/²log x - ˣlog (x+6) + ˣ⁺²logx = 1
ˣlog (2x-3) - ˣlog (x+6) + log (x+2)/log x = 1
ˣlog (2x-3) - ˣlog (x+6) + ˣlog (x+2) = ˣlog x
ˣlog (2x-3)(x+2)/(x+6) = ˣlog x
(2x-3)(x+2)/(x+6) = x
(2x-3)(x+2) = x(x+6)
2x² + x - 6 = x² + 6x
x² - 5x - 6 = 0
(x+1)(x-6) = 0

x₁ = -1
x₂ = 6