gimana nih.? tolong beserta caranya

Mapel : Matematika
Bab : Akar dan Pangkat

[tex]4 ^{ \frac{3}{2} } 3 ^{ \frac{1}{2} } 12 ^{ \frac{1}{2} } \\ = 4 ^{ \frac{3}{2} } \times 3 ^{ \frac{1}{2} } \times 12 ^{ \frac{1}{2} } \\ = (2 ^{2} ) ^{ \frac{3}{2} } \times \sqrt{3} \times \sqrt{12} \\ = 2 ^{3} \times \sqrt{(3 \times 12)} \\ = 8 \times \sqrt{36} \\ = 8 \times 6 \\ = 48[/tex]

Jawaban : C. 48

Maaf Kalau Salah

4^3/2 × 3^1/2 × 12^1/2
=akar 4^3 × akar 3 × akar 12
=akar 64 × akar 3 × akar 12
=8 × akar 36
=8 × 6
=48 (C)