tolong dibantu dong.. dijawab pake caranya ya..

6) Titik Pojok :
(x,y) = (12,0) , (8,0) ,(xp,yp)
xp dan yp adalah titik potong kedua garis
persamaan garis :
6x + 12y <= 72 atau x + 2y <= 12
8x + 8y >= 64 atau x + y >= 8
___________-
y = 4
maka x = 4
(xp,yp) = (4,4)

Masukkan nilai titik pojok ke fungsi objektif
f(x,y) = 2x + 7y
f(12,0) = 2.12 = 24
f(8,0) = 2.8 = 16
f(4,4) = 2.4 + 7.4 = 36

Jadi nilai maksimumnya adalah 36 (C)

17.
[ 3 -2 ] - 3[2 1 ] = [-3 -5 ]
[-4 2p] - [ q 3] = [ 2 1 ]

[ 3 -2 ] - [6 3] = [ - 3 -5 ]
[ -4 2p]-[ 3q 9] = [ 2 1 ]

[ -3 -5 ] = [ -3 -5 ]
[ -4-3q 2p - 9 ] = [ 2 1 ]

-4 - 3q = 2
3q = -6
q = -2

2p - 9 = 1
2p = 10
p = 5

3p + 2q = 15 - 4= 11

smg membantu :)