Diketahui log 2 = a, log 3 = b, log 5 = c. Nilai log 27/40 = ... a. 3a + 3b - c b. 3b - 3a - c c. 3a - b - 3c d. 3a - 3b - c

Question

Matematika Diposting : 2017-12-27 Diupdate : 2022-01-05 Jocelyn150203

Pertanyaan

Diketahui log 2 = a, log 3 = b, log 5 = c.
Nilai log 27/40 = ...
a. 3a + 3b - c
b. 3b - 3a - c
c. 3a - b - 3c
d. 3a - 3b - c

Answer 1

log27-log40=3(log3)-(3(log2)+(log5))=3b-3a-c jawab b