1. Hitunglah hambatan pengganti, kuat arus pada rangkaian, kuat arus pada hambatan 6 Ohm, kuat arus pada hambatan 3 ohm, 2. Sebuah keluarga berlangganan listrik

1. a. 1/Rp = 1/6 + 1/3 = 1/6 + 2/6 = 3/6 Rp = 6/3 = 2 Rtot = 2 + 2 = 4 ohm. b. I = V : R = 12 : 4 = 3 A c. I = V : R = 12 : 6 = 2 A d. I = V : R = 12 : 3 = 4 A 2. Lampu = 6 x 20 x 5 = 600 wh Televisi = 3 x 300 = 900 wh Pompa air = 2x 125 = 250 wh Kulkas = 100 x 24 = 2400 wh Setrika = 300 x 2 = 600 wh Total = 4750 wh = 4.75 kwh x 1000 x 30 = 142500

1. Diketahui = R1 = 2 Ohm
R2 = 6 Ohm
R3 = 3 Ohm
V = 12 V
Ditanya = a. Rp b. I c. I1 d. I2
Jawab = a. 1/Rp = 1/R2 + 1/R3
= 1/6 + 1/3
= 1+2/6
= 3/6
Rp = 6/3 = 2 Ohm

1/Rptotal = 1/R1 + 1/Rp
= 1/2 + 1/2
=1+1/2
= 2/2
Rp = 2/2 = 1 Ohm

b. I = V/Rp
= 12 V/ 1 Ohm
= 12 Ampere

c. I1 = V/R2
= 12 V/ 6 Ohm
= 2 Ampere

d. I2 = V/R3
= 12 V/ 3 Ohm

2. Diketahui =
W1 = 6lampu × 20
watt × 5 hours
= 6.000 wh
W2 = 1 × 300 watt ×
3 h = 900 wh
W3 = 1 × 125 watt ×
2 h = 250 wh
W4 = 1 × 100 watt ×
24 h =2400 wh
W5 = 1 × 300 watt ×
2 h = 600 wh
per kwh = Rp1.000

Jawab = w sehari =
(600+900+250
2400+600) wh
= 10150wh/1000
= 10,15 kwh
w sebulan = 10,15 kwh ×
30 = 304.5
kwh
Biaya = Rp1000 ×
304,5 kwh
= Rp304.500