tolong di jawab ya kak no 8 sma caranya

AB = 7 cm
BC = 5 cm
AC = 6 cm
Ditanya : sin <BAC
Jawab
Teorema Cosinus
cosBAC = (AB^2 + AC^2 - BC^2)/2AC×AB
cosBAC = (7^2 + 6^2 - 5^2) / 2.6.7
cosBAC = (49 + 36 - 25) / 2.6.7
cosBAC = 60/2.6.7
cosBAC = 5/7

sinBAC = (akar(7^2 - 5^2))/7 ---> diperoleh dari teorema phytagoras
sinBAC = (akar(49-25))/7
sinBAC = (akar 24) /7
sinBAC = 2/7 akar6 (B)

smg membantu