melengkapkan kuadrat sempurna 6x^{2}+10x-8= ?

jawab

6x² + 10x - 8 = 0

x² + 10/6 x - 8/6  = 0

x² + 5/3 x  - 4/3 = 0

x² + 5/3 x = 4/3

(x + 5/6)²  = 4/3 + (5/6)² = 4/3 + 25/36 

(x + 5/6)² = 73/36

x+ 5/6 = √(73/36)

x + 5/6 = +- 1/6 √73

x =  5/6 + 1/6 √73  atau x = 1/6 ( 5 + √73)

x = 5/6 - 1/6 √73  atau x = 1/6 (5 - √73)