Diket:Q1 = 4×10-² c Q2= 3×10-⁴c r= 4 m K = 9.10(pangkat 9) nm²/c² Ditanya f...? Jawab?
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Pertanyaan
Diket:Q1 = 4×10-² c
Q2= 3×10-⁴c
r= 4 m
K = 9.10(pangkat 9) nm²/c²
Ditanya f...?
Jawab?
Q2= 3×10-⁴c
r= 4 m
K = 9.10(pangkat 9) nm²/c²
Ditanya f...?
Jawab?
1 Jawaban
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1. Jawaban Fatahira
|LISTRIK STATIS|
Gaya Coulomb - kls : 9
Diket : Q1 = 4.10^-2 C
Q2 = 3.10^-4 C
r = 4 m
Dit : Fc =..........?
Penyelesaian :
Fc = K.Q1.Q2 / (r)²
= 9.10^9.4.10^-2.3.10^-4 / (4)²
= 9.4.3.10^9+(-2)+(-4) / 16
= 27.10^3 / 4
= 6,75 N