diketahui log 2=0,301 ; log 3 =0,477 dan log 7 =0,485 tentukan ! A. 9log18

Kelas 10 Matematika
Bab Logaritma

^ = pangkat

^9log 18
= ^9log (2 . 9)
= ^9log 2 + ^9log 9
= (log 2 : log 9) + 1
= (0,301 : log 3²) + 1
= (0,301 : (2 . log 3)) + 1
= (0,301 : (2 . 0,477)) + 1
= (0,301 : 0,954) + 1
= 0,3155 + 1
= 1,3155