tolong jawab yang a sampai e jangan ngawur

a. 3^-5 × 3^3 ÷ 3^-4
= 3^(-5 + 3 - 4)
= 3^-6

b. (2^-4 × 2^2) / (2^-1 × 2^5)
= 2^(-4 + 2) / 2^(-1 + 5)
= 2^-2 / 2^4
= 2^(-2 - 4)
= 2^-6

c. (0,25)^-2 × (0,25)^4
= 1/4^-2 × 1/4^4
= 2^4 × 2^-8
= 2^(4 + (-8))
= 2^-4

d. (2 × 7)^3 × 7^2 × 1/(2 × 7)^5
= (2 × 7)^3 × (2 × 7)^-5 × 7^2
= (2 × 7)^(3 - 5) × 7^2
= (2 × 7)^-2 × 7^2
= 2^-2 × 7^-2 × 7^2
= 2^2 × 7^(-2 + 2)
= 2^2 × 7^0
= 2^2 × 1
= 2^2

e. ((3^0 × 5^2/ 5^2)^2)^3
= ((1 × 5^(2 - 2))^2)^3
= ((1 × 5^0)^2)^3
= ((1 × 1)^2)^3
= (1^2)^3
= 1^3
= 1