ada yg bisa jawab nmr 23 ga

Jadi ini solusinya hehe

energi kinetik=
[tex] \frac{1}{2} \times m \times v {}^{2} [/tex]
=
[tex] \frac{1}{2} \times 5 \times \frac{240}{20} {}^{2} [/tex]
=
[tex] \frac{1}{2} \times 5 \times 12 {}^{2} [/tex]
=1/2*5*144
=360 joule

semoga membantu