persamaan a(3,-2) Dan b (-1,3)

jawab

garis AB  = 

y -y1/(y2 - y1) = (x - x1)/(x2 - x1)
y + 2 / (5) = (x - 3)/(-4)
-4(y +2) = 5(x - 3)
- 4y -8 = 5x - 15
5x + 4y - 7 = 0

y-y1 / y2-y1 = x-x1 / x2-x1
y + 2 / 5 = x - 3 / - 4
-4(y+2) = 5(x-3)
kalikan
-4y - 8 = 5x - 15
samakan suku
5x + 4y - 15 + 8 = 0
5x + 4y - 7 = 0