carilah fungsi F, jika f'(x)=3(x²-3)dan f(-1)=2

jawab

f(x) = ∫ 3x² -9 dx
f(x) = x³ - 9x + c
f(-1) = 2
 -1 + 9 + c = 2
8 + c = 2
c= - 6
f(x) = x³ -9x - 6