Diketahui f(x)=2x-1 ,g(x)=3x+2 dan (f°g)(p)=33. Nilai p=

Kelas 10 Matematika
Bab Fungsi Komposisi

(fog) (p) = 33
f(3p + 2) = 33
2(3p + 2) - 1 = 33
6p + 4 - 1 = 33
6p = 33 - 3
p = 30/6
p = 5

(Fog) = 2(3x+2)-1
= 6x+4-1
= 6x+3
6x+3=33
6x=30
X=5