diketahui log2=0,301 dan log3=0,477. Nilai log akar 6=

Kelas 10 Matematika
Bab Logaritma

^ = pangkat

log √6
= log 6^(1/2)
= (1/2) . log 6
= (1/2) . (log (2 . 3))
= (1/2) . (log 2 + log 3)
= (1/2) . (0,301 + 0,477)
= (1/2) . 0,778
= 0,389

Log6=log2.3=log2+log3=0,301 + 0,477 = 0,778


Caman itu jawaban saya semoga bermanfaat..maaf ya kalau jawabannya salah