Matematika

Pertanyaan

2. 3log6 -1/2. 3log16+3log18-3log2

1 Jawaban

  • Kelas 10 Matematika
    Bab Logaritma

    ^ = pangkat

    2 . ^3log 6 - (1/2) . ^3log 16 + ^3log 18 - ^3log 2
    = ^3log 6² - ^3log 16^(1/2) + ^3log (18/2)
    = ^3log 36 - ^3log 4 + ^3log 9
    = ^3log (36/4) + ^3log 3²
    = ^3log 9 + 2 . ^3log 3
    = ^3log 3² + 2
    = 2 . 1 + 2
    = 4

Pertanyaan Lainnya