Diketahui : f(x)= 2x+1 g(x)=x+2 / 2x-3 nilai (f°g)(1)=.....

(f o g)(x) = 2(x+2/2x-3) + 1 = (2x+4/2x-3) + 1

(f o g)(1) = (2.1+4/2.1 - 3) + 1 = (6/-1) +1 = -6+1 = -5

Materi : Fungsi Komposisi

f(x) = 2x + 1
g(x) = (x + 2) / (2x - 3)

maka
g(1) = (1 + 2) / (2(1) - 3)
g(1) = 3/-1 = -3

f(-3) = 2(-3) + 1
f(-3) = -6 + 1
f(-3) = -5

jadi 
(fog)(1) 
= f(g(1))
= f(-3)
= -5