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diket: vektor u = 2i-4j-6k
vektor v = 2i-2j+4k
dit c ( proyeksi ortogonal vektor u pada vektor v) ?
jawab: c = vektor u × vektor v/ |vektor v|^2 × vektor v
c= (2, -4, -6)×(2,-2,4)/ (akar 2^2+-2^2+4^2)^2 × (2i-2j+4k)
= 4+8-24/4+4+16 ×(2i-2j+4k)
= -12/24×(2i-2j+4k)
= -i+j-2k (c)