Mohon bantuannya kaak Jika f(x)=x^2-2x+4 (fog)(x)=4x^2+3 g(-2)=-3 maka nilai g(-3)=?

f(x) = x^2 - 2x + 4
(f○g)(x) = 4x^2 + 3
g(-2) = -3
g(-3) = ....???

(f○g)(x) = 4x^2 + 3
f(g(x)) = 4x^2 + 3
(g(x))^2 - 2(g(x)) + 4 = 4x^2 + 3
(g(x))^2 - 2(g(x)) = 4x^2 + 3 - 4
(g(x))^2 - 2(g(x)) = 4x^2 - 1
(g(x) - 1)^2 - 1 = 4x^2 - 1
(g(x) - 1)^2 = 4x^2 - 1 + 1
(g(x) - 1)^2 = 4x^2
g(x) - 1 = V(4x^2)
g(x) - 1 = 2x
g(x) = 2x + 1

g(x) = 2x + 1
g(-2) = 2(-2) + 1
g(-2) = -4 + 1
g(-2) = -3

g(x) = 2x + 1
g(-3) = 2(-3) + 1
g(-3) = -6 + 1
g(-3) = -5

Jadi nilai g(-3) adalah -5