(27)^2/3 + (16)^3/4 - (8)^2/3 dan cara

Kelas 9 Matematika
Bab Akar dan Pangkat

^ = pangkat

27^(2/3) + 16^(3/4) - 8^(2/3)
= (3^3)^(2/3) + (2^4)^(3/4) - (2^3)^(2/3)
= 3² + 2^3 - 2²
= 9 + 8 - 4
= 13

[tex] {27}^{ \frac{2}{3} } + {16}^{ \frac{3}{4} } - {8}^{ \frac{2}{3} } \\ = ( {3}^{3} )^{ \frac{2}{3} } + ({ {2}^{4} })^ {\frac{3}{4}} - ( { {2}^{3} })^{ \frac{2}{3} } \\ = {3}^{2} + {2}^{3} - {2}^{2} \\ = 9 + 8 - 4 \\ = 13[/tex]
Semoga dapat dipahami