3. Tentukan massa molekul relatif (Mr) pada senyawa berikut: a. C6H12O6 b. H2SO4 c. CH3COOH d. Pd(NH3)4 e. KH2O (Ar. C=12 H=1 S=32 O=16 N=14 K=39 Pt=195)

a. Mr C6H12O6
= (ar C x 6) + (ar H x 12) + (ar O x 6)
= (12 x 6) + (1 x 12) + (16 x 6)
= 72 + 12 + 96
= 180 gr/mol

b. Mr H2SO4
= (ar H x 2) + (ar S x 1) + (ar O x 4)
= (1 x 2) + (32 x 1) + (16 x 4)
= 2 + 32 + 64
= 98 gr/mol

c. Mr CH3COOH
= (ar C x 1) + (ar H x 3) + (ar C x 1) + (ar O x 1) + (ar O x 1) + (ar H x 1)
= (12 x 1) + (1 x 3) + (12 x 1) + (16 x 1) + (16 x 1) + (1 x 1)
= 12 + 3 + 12 + 16 + 16 + 1
= 60 gr/mol

d. Mr Pt(NH3)4
= (ar Pt x 1) + (ar N x 4) + (ar H x 12)
= (195 x 1) + (14 x 4) + (1 x 12)
= 195 + 56 + 12
= 263 gr/mol

e. Mr KH2O
= (ar K x 1) + (ar H x 2) + (ar O x 1)
= (39 x 1) + (1 x 2) + (16 x 1)
= 39 + 2 + 16
= 57 gr/mol