Faktor persekutuan dari 8x²-10x-12 dan 16x²-9 adalah... A. (4x-9) B. (2x-3) C. (4x-3) D. (4x+3)

[tex]faktor \: \: 8 {x}^{2} - 10x - 12 \\ 8 {x}^{2} - 10x - 12 = 2(4 {x}^{2} - 5x - 6) \\ 2(4 {x}^{2} - 5x - 6) = 0 \\ 2(4x + 3)(x - 2) = 0 \\ \\ faktor \: \: 16 {x}^{2} - 9 \\ 16 {x}^{2} - 9 = 0 \\ (4x - 3)(4x + 3) = 0 \\ \\ faktor \: \: persekutuan \: = \\ (4x + 3)[/tex]
Jawaban D