ditentukan f(x)=-x+2, dengan daerah asal (x|-3lebih kecil sama dengan x <3, x bilangan bulat). daerah hasil fungsi tersebut adalah

Daerah asal
= {x|-3≤x<3, x € bilangan bulat}
= {-3,-2,-1,0,1,2}

f(x) = -x + 2
Daerah hasil = {.......}
f(-3) = -(-3)+2 = 3 + 2 = 5
f(-2) = -(-2)+2 = 2 + 2 = 4
f(-1) = -(-1)+2 = 1 + 2 = 3
f(0) = -(0)+2 = 0 + 2 = 2
f(1) = -(1)+2 = -1 + 2 = 1
f(2) = -(2)+2 = -2 + 2 = 0

Daerah hasil
= {5,4,3,2,1,0}

jawab

f(x) = - x + 2
x = (--3, - 2, - 1, 0, 1, 2}

x = - 3 -> f(-3) = -(-3) + 2 = 5
x = -2 -->f(-2) = -(-2) + 2 = 4
x = -1 --> f(-1) = - (-1) + 2 = 3
..
x = 2 ---> f(2) = - 2 + 2= 0

Daerah hasil f(x)  = (0,1,2,3,4,5}