Butuh bantuan teman2. Trims banyak

¹²⁵log (2x-3)⁻¹ = ²⁵log (5x²-20x+24)⁻¹/³

log (2x-3)⁻¹/log 125 = log (5x²-20x+24)⁻¹/³ / log 25

log (2x-3)⁻¹/log 5³ = log (5x²-20x+24)⁻¹/³ / log 5²

-1 log (2x-3) / 3 log 5 = -1/3 log (5x²-20x+24) / 2 log 5

-1/3 log (2x-3) = -1/3 x 1/2 log (5x²-20x+24)

log (2x-3) = 1/2 log (5x²-20x+24)

2 log (2x-3) = log (5x²-20x+24)

log (2x-3)² = log (5x²-20x+24)

hilangkan log

(2x-3)² = (5x²-20x+24)

4x²-12x+9 = 5x²-20x+24

x²-8x+15 = 0

(x-3)(x-5)

x₁ = 3
x₂ = 5

Semoga membantu ya dan selamat mencoba.