tolong dijawab dengan cara ,makasih

a) garis melalui (-4 , 0) dan (0, 2)
(y - y1)/(y2 - y1) = (x - x1)/(x2 - x1)
(y - 0)/(2 -0) = (x - -4)/(0 - - 4)
y/2 = (x +4)/4
4y = 2x + 8
y = (2x +8)/4
y = (1/2)x + 2
b) garis sejajar k, melalui (1, -2). maka gradien 1/2
y - 1 = m (x - -2)
y - 1 = 1/2 (x - - 2)
y - 1 = 1/2 (x +2)
y - 1 = 1/2x + 1
y = 1/2x + 1 +1
y = (1/2)x + 2
c) tegak lurus, misal gradien m2
m1.m2 = -1
1/2.m2 = -1
m2 = -2. melalui (-3, 4)
y - y1 = m2 (x - x1)
y - 4 = -2(x - -3)
y - 4 = -2(x + 3)
y - 4 = -2x -6
y = -2x -2