please bantu dengan caranya ya

(y-y1)/(y2-y1) = (x-x1)/(x2-x1)
(y-3) / (-2-3) = (x-2) / (4-2)
(y-3)/-5= (x-2) / 2
2(y-3)= -5(x-2)
2y-6 = -5x+10
2y = -5x+(6+10)
2y=-5x+16
5x+2y-16=0 (b)