1. ∫ x √3-x^2 dx 2. ∫ cos (3-5x) dx 3. ∫ √3-5x dx

jawab

1)
∫ (x√3  - x²) dx

= √3 (1/2 x²)  - 1/3 x³ + c
= 1/2 √3 x²  - 1/3 x³ + c
= 1/6 x² ( 3√3 - 2 x) + c

2)
∫ cos (3 - 5x) dx
u = 3 - 5x
du = - 5 dx
dx = - 1/5 du
∫- 1/5 cos u du = - 1/5 sin u + c
= - 1/5 sin (3 - 5x)

3)
∫ √(3 - 5x) d

u = 3 - 5x
du = -5 dx
dx = - 1/5 du
∫ - 1/5 u^(1/2)  du =
= - 1/5 { 2/3  u^(3/2) ] + c
=  - 2/15 . u √ u + c
= - 2/15 (3- 5x) √(3 - 5x) + c