Matematika

Pertanyaan

Minta tolong kakak sekalian!
Minta tolong kakak sekalian!

2 Jawaban

  • f(x) =ax+b

    f(-2) =ax+b
    =a(-2)+b
    14 = -2a+b
    14+2a=b

    f(3) =a(3)+b
    -1 =3a+b
    -1 =3a+(14+2a)
    (-1)-14=3a+2a
    -15 =5a
    a = -15÷5
    a= -3


    b=14+2a
    b=14+2.(-3)
    b=14+(-6)
    b=8

    f(x)=ax+b
    f(7)= (-3).7+8
    = (-21)+8
    = -13/A

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  • jawab

    f(x)= ax + b
    f(-2) = 14
    f(3) = -1

    (-2-3)a =  14 - (-1)
    -5a = 15
    a = - 3

    f(3) = - 1
    b = -1 -3a
    b = -1 -3(-3)
    b = -1 + 9
    b = 8

    f(7) = -3(7) + 8
    = -21 +8
    = - 13