Minta tolong kakak sekalian!
Matematika
Khaywa
Pertanyaan
Minta tolong kakak sekalian!
2 Jawaban
-
1. Jawaban aninfitria
f(x) =ax+b
f(-2) =ax+b
=a(-2)+b
14 = -2a+b
14+2a=b
f(3) =a(3)+b
-1 =3a+b
-1 =3a+(14+2a)
(-1)-14=3a+2a
-15 =5a
a = -15÷5
a= -3
b=14+2a
b=14+2.(-3)
b=14+(-6)
b=8
f(x)=ax+b
f(7)= (-3).7+8
= (-21)+8
= -13/A
#smoga bisa membantu -
2. Jawaban Anonyme
jawab
f(x)= ax + b
f(-2) = 14
f(3) = -1
(-2-3)a = 14 - (-1)
-5a = 15
a = - 3
f(3) = - 1
b = -1 -3a
b = -1 -3(-3)
b = -1 + 9
b = 8
f(7) = -3(7) + 8
= -21 +8
= - 13