2log24 + 2log8 - 2log6=

Mata Pelajaran : Matematika Peminatan
Kelas : 10
Bab : 02 - Fungsi Logaritma



²log24 + ²log8 - ²log6
→ ²log ( (24 x 8) / 6 )
→ ²log (4x8)
→ ²log32
→ ²log(2⁵)
→ 5.²log2
→ 5 x 1 = 5

[tex] {}^{2} log \: 24 + {}^{2} log \: 8 - {}^{2} log \: 6 = \\ = ({}^{2} log \: 2 {}^{3} + {}^{2} log \: 3) + {}^{2} log \: 2 {}^{3} - ({}^{2} log \: 3 + {}^{2} log \: 2) \\ = 3. {}^{2} log \: 2 + {}^{2} log \: 3 + 3. {}^{2} log \: 2 - {}^{2} log \: 3 - {}^{2} log \: 2 \\ = 3 + 3 - 1 \\ = 5 [/tex]
maaf, kalau salah
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