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Kelas 9 Matematika
Bab Akar dan Pangkat

(1/(3 + 2√2))² - (1/(3 - 2√2))²
= ((1/(3 + 2√2)) + (1/(3 - 2√2))) . ((1/(3 + 2√2)) - (1/(3 - 2√2)))
= ((3 - 2√2 + 3 + 2√2)/(3² - (2√2)²)) . ((3 - 2√2 - 3 - 2√2)/(3² - (2√2)²)
= (6/(9 - 8)) . ((-4√2)/(9 - 8))
= 6 . (-4√2)
= -24√2

[tex]a = \frac{1}{3 + 2 \sqrt{2} } \times \frac{3 - 2 \sqrt{2} }{3 - 2 \sqrt{2} } = 3 - 2 \sqrt{2} \\ b = \frac{1}{3 - 2 \sqrt{2} } \times \frac{3 + 2 \sqrt{2} }{3 + 2 \sqrt{2} } = 3 + 2 \sqrt{2} \\ {a}^{2} - {b}^{2} \\ = {(3 - 2 \sqrt{2} )}^{2} - {(3 + 2 \sqrt{2} )}^{2} \\ = 9 - 6 \sqrt{2} - 6 \sqrt{2} + 8 - 9 - 6 \sqrt{2} - 6 \sqrt{2} - 8 \\ = - 12 \sqrt{2} - 12 \sqrt{2} \\ = - 24 \sqrt{2} [/tex]