Matematika

Pertanyaan

tentukan hasil integral dari: int 8x^5-3/23x^3 dx ? mohon bantuannya

1 Jawaban

  • [tex]\displaystyle \int\frac{8x^5-3}{23x^3}\,dx=\int\frac{8}{23}x^2-\frac{3}{23x^3}\,dx\\\int\frac{8x^5-3}{23x^3}\,dx=\int\frac{8}{23}x^2-\frac{3}{23}x^{-3}\,dx\\\int\frac{8x^5-3}{23x^3}\,dx=\frac{8}{23}\cdot\frac1{2+1}x^{2+1}-\frac{3}{23}\cdot\frac{1}{-3+1}x^{-3+1}+C\\\int\frac{8x^5-3}{23x^3}\,dx=\frac{8}{23}\cdot\frac1{3}x^{3}-\frac{3}{23}\cdot\frac{1}{-2}x^{-2}+C\\\boxed{\boxed{\int\frac{8x^5-3}{23x^3}\,dx=\frac{8}{69}x^{3}+\frac{3}{46x^2}+C}}[/tex]

Pertanyaan Lainnya