Tolong dibantu jawab yang no 4 bab segitiga

Diket :
a = 18cm
t1 = 15cm
t2 = 6cm
t3 = 24cm

Jawab :
luas 1 = a x t1/2 = 18 x 15/2 = 135 cm^2
luas 2 = a x t2/2 = 18 x 6/2 = 54 cm^2
luas 3 = a x t3/2 = 18 x 24/2 = 216 cm^2

Luas total = (L1-L2)+(L3-L2)
Luas total = (135-54)+(216-54)
Luas total = 81+162 = 243 cm^2

Maaf jika ad kesalahan :)

Lsegitiga = ½.a. t
segitiga1 = ½.18.6 = 54 cm²
segitiga2 = ½.18.15 = 135 cm²
segitiga3 = ½.18.24 = 216 cm²

Luas daerah yg diarsir
= ( 135 - 54 ) + ( 216 - 54 ) = 81 × 162 = 243 cm² (C)