Matematika

Pertanyaan

Integral 2 sin t dt [ve/2, ve/6]

1 Jawaban

  • jawab


    ∫ 2 sin t dt [ π/2, π/6]


    = -2 [ cos t ]  {pi/2 , pi/6}

    =  - 2 [ cos pi/2 - cos pi/6 ]

    = - 2 [ 0 - 1/2 ]

    = 1

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