Integral tentu [1,8] akar 3 dari w dw

jawab


[1,8]∫ ∛w dw

= 3/4 [ w]^(4/3) [1 8]

= 3/4 [8^(4/3) - (1)^(4/3)]

= 3/4 [ 2^4  - 1]

= 3/4 (15)

= 45/4