tolong buat cara yaa

Jawab :

A(10,p) terletak pd garis BC
B(3,1)
C(-4,-13)

gradien = ∆y / ∆x

mAB = mBC
(p - 1)/(10 - 3) = (1 - (-13))/(3 - (-4))
(p - 1)/7 = 14/7
p - 1 = 14
p = 15 ✔

jawab

A, B , C segaris
p= 15