jika [tex] ^{5} log_{3} = p \: maka ^{15} log(81) [/tex] adalah...

Jawab :

5'log 3 = p

81'log 15
= log 15 / log 3⁴
= 1/4 (³log 15)
= 1/4 (³log 3 + ³log 5)
= (1 + 1/p)/4
= (p + 1) / 4p

15'log 81
= 1/ (81'log 15)
= 4p/(p + 1)

5log 3 = p
15log 81 = ...
log 81 / log 15
log 3^4 / log 3.5
4.log 3 / (log 3 + log 5). beri bilangan pokok baru 3, maka
4.(3log 3)/ (3log 3 + 3log 5)
4.1 / ( 1 + 1/p)
= 4 / { (p+1)/p }
= 4p / p+1