cari turunan dy/dx dari (2x-3)/(x^2+4)^3

jawab

y = (2x - 3)/ (x² + 4)³
y = (2x - 3)(x² +4)⁻³ 
y= u v

y' = u' v + uv'

y' = 2(x²+ 4)⁻³ + (2x-3) (-3)(2x)(x²- 4)⁻⁴
y' = 2(x² +4)⁻³ - 6x(2x- 3) (x² -4)⁻⁴
y' = 2(x²+4)⁻⁴  [x²+ 4 - 12x² + 18 x]
y' = 2(-11x² + 18x + 4)/(x² + 4)⁴
y' = (-22x² + 36x + 8) / (x² +4)⁴