tolong diselesaikan berserta jalan kerjanya

PK : 3x^2 + px + 8 = 0
akar-akarnya x1 dan x2 dengan x1 = a dan x2 = 2/3a.
x1 + x2 = -p/3.=> a + 2/3a = -p/3
(5/3)a = -p/3 => 5a = -p =>p = -5a
x1.x2 = 8/3
a.2/3a = 8/3
2a^2 = 8
a^2 = 4
a = +/-√4
a = +/- 2
p1 = -5.2 = -10
p2 = -5.-2 = 10