mohon bantuannya guys

Integral

Jawaban di gambar

J (x - 2)(2x +5) dx. ( J maksudnya integral)
= J ( 2x^2 + x -10) dx.
= (2/3)x^3 + (1/2)x^2 - 10x , batas 0 ==> 3
= { (2/3)(3^3)+ (1/2)(3^2) -10(3) } - { 0 }
= 18 +9/2 -30
= -12 + 9/2
= -24/2 + 9/2
= -15/2
= -7,5. => - 7 1/2 ..e.