jika f1(X)=2x-3 dan f(2)=0 maja f(X)

jawab

f' (x ) = 2x - 3

f(x)= ∫ f'(x) dx
f(x) = ∫ (2x - 3) dx
f(x) = x² - 3x + c
f(2)= 0
2²- 3(2) + c = 0
4 - 6 + c = 0
-2 + c = 0
c= 2

f(x) = x² - 3x + 2