Tentukan dy/dx dari fungsi implisit √y + xy^2 =5 Mohon bantuannya gan

[tex] \sqrt{y} +xy^2=5 \\ \frac{1}{2\sqrt{y}} * \frac{dy}{dx} +y^2+2xy*\frac{dy}{dx} =0 \\ \frac{dy}{dx} = -\frac{y^2}{\frac{1}{2\sqrt{y}}+2xy} = -\frac{2y^2\sqrt{y}}{1+4xy\sqrt{y}}[/tex]