jika 23^n = 5 dan 23^m = 10 maka nilai dari 2 1/n-m

23^n = 5
n = 23log5

23^m = 10
m = 23log10

2^(1/(n-m)) = 2^(1/(23log5-23log10))
= 2^(1/(23log(5/10)))
= 2^(1/(23log(1/2)))
= 2^((1/2)log23)
= 2^(2^(-1)log23)
= 2^(-2log23)
= (2^(2log23))^(-1)
= 23^(-1)
= 1/23

23^n = 5
n = 23log5

23^m = 10
m = 23log10

2^(1/(n-m)) = 2^(1/(23log5-23log10))
=2^(1/(23log(5/10)))
=2^(1/(23log(1/2)))
=2^((1/2(log23)
=2^(2^(-1)log23)
=2^(-2log23)
=(2^(2log23))^(-1)
=23^(-1)
=1/23