Matematika

Pertanyaan

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1 Jawaban

  • 29) BC = 10/ cos 30
    = 10/ ½√3
    = 20/3 √3

    30) OF = garis dr titik F ke garis AC
    OB = ½ s√2
    = ½.12 √2
    = 6√2

    BF = 12

    OF = √OB²+BF²
    = √(6√2)²+12²
    = √36.2 + 144
    = √36(2+4)
    = 6√6

    31) BP = √1²+½²
    = √1+¼
    = √5/4
    = ½√5

    PG = ½
    BG = √2

    Cos PBG = BP²+BG²-PG² / 2.BP.BG
    = (5/4 +2- ¼) / (2.½√5.√2)
    = 3 /√10

    Sin PBG = ¹/10 √10