Fungsi f dinyatakan dgn rumus f(x)=ax + b , jika f(0)=4 dan f(2)=10. Tentukan nilai f(9)

f(x) = ax + b

f(0) = a.0 + b
4 = b

f(2) = 2a + b
10 = 2a + 4
2a = 6
a = 3

f(9) = 9a + b
= 9.3 + 4
= 27 + 4
= 31

smg membantu :)

f(x)=ax+b
f(0)=a(0)+b=4
=0a+b=4 (i)
f(2)=a(2)+b=10
=2a+b=10 (ii)
eliminasi (i) & (ii)
0a+b=4
2a+b=10
------------ —
-2a=-6
a=3

2a+b=10
2(3)+b=10
b=10-6
b=4

jadi nilai a=3 & b=4
f(x)=3x+4