no 10 tinggal 1 ......

jawab

t1= 4
t2 = (4+3) = 7
t3 = 12
r3 = 12

t1/r1 = t3/r3
4/r1  = 12/12
r1 = 4

t2/r2 = t3/r3
7/r2 = 12/12
r2= 7

Volume yg diarsir = V2 - v1

V = 1/3 π ( r2² t2 - r1² . t1)
V = 1/3 π (7²,7² - 4².4)
V = 1/3 π(7³-4³)
V = 1/3 π(279(
V = 93 π