carilah gradien dari persamaan x²-y²+4xy = 12y dititik (2,1) !

jawab

x²  - y² + 4xy = 12y
2x - 2yy' + 4y + 4xy' = 12yy'
-2yy' + 4xy - 12yy' = -2x - 4y
y' (-2y + 4x -12y) = -2x - 4y
y' = (- 2x - 4y)/(-2y + 4x -12y)

m = y'
m di titik (x,y)=(2,1)
m = (- 2(2) - 4(1)) / ( - 2(1) +4(2) -12(1))
m = (-4 - 4)/ (-2 +8 -12)
m = -8/-6
m = 4/3