tolongiiiiiiiiinnnnnnnn

2/x - 1/y - 3/z = -1...(1)
2/x - 1/y + 1/z = -9...(2)
1/x +2/y - 4/z = -17...(3)
ambil (1) dan (2)
2/x -1/y -3/z = - 1....(1)
2/x -1/y +1/z = -9
--------------------------- -
-4/z = 8 => z = -4/8 = -1/2....(4)
ambil (1) dan (3), eliminasi x, maka (3)×2
2/x -1/y-3/z = -1...(1)
2/x + 4/y -8/z = -34
----------------------------- -
-5/y -5/z = 33. => subsitusikan z = -1/2
-5/y -5(-1/2) = 33
-5/y + 10 = 33
-5/y = 23
y = -5/23
darj (1) => 2/x - 1/y -3/z = -1
2/x - 1/(-5/23) -3/(-1/2) = -1
2/x + 23/5 +6 = -1
2/x + 53/5 = -1
2/x = - 1 - 53/5
2/x = -58/5
x = -5/29
5x -5y + z = 5(-5/29) -5(-5/23) + -1/2
= -25/29 + 25/23 -1
= ..... teruskan..! semoga membantu.