Minta bantuannya sama caranya plissss

Mapel : Matematika
Bab : Akar dan Pangkat

Diketahui :
- p = 2/(√2 + 3)
- q = 3/(√2 - 3)

Ditanya :
- Nilai p - q = ....?

Penyelesaian :
- Nilai p - q :

[tex] \frac{2}{ \sqrt{2} + 3 } - \frac{3}{ \sqrt{2} - 3 } \\ = \frac{2( \sqrt{2} - 3) - 3( \sqrt{2} + 3) }{( \sqrt{2} + 3)( \sqrt{2} - 3)} \\ = \frac{2 \sqrt{2} - 6 - 3 \sqrt{2} - 9}{2 - 9} \\ = \frac{2 \sqrt{2} - 3 \sqrt{2} - 6 - 9}{ - 7} \\ = \frac{ - \sqrt{2} - 15}{ - 7} \\ = \frac{ \sqrt{2} + 15}{7} \\ = \frac{1}{7} ( \sqrt{2} + 15) \\ = \frac{1}{7} (15 + \sqrt{2} )[/tex]

Jawaban : B. ⅐(15 + √2)

Maaf Kalau Salah

Soal
Jika p = 2 / √2 + 3 dan q = 3 / √2 - 3
Maka p - q = ...

Penyelesaian
p - q
= 2 / √2 + 3 - 3 / √2 - 3
= 2(√2 - 3) - 3(√2 + 3) / (√2 + 3)(√2 - 3)
= 2√2 - 6 - 3√2 - 9 / 2 - 3√2 + 3√2 - 9
= -√2 - 15 / -7
= √2 + 15 / 7
= 1/7 (15 + √2) (B)